document.write( "Question 102644: Can you help me find the slope of the line that passes through (7, -8) and is perpendicular to 3y = x = 6\r
\n" ); document.write( "\n" ); document.write( "PLEASE, and thanks to anyone who helps !
\n" ); document.write( "

Algebra.Com's Answer #74667 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "First convert the standard equation \"x%2B3y=6\" into slope intercept form\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Converting Linear Equations in Standard form to Slope-Intercept Form (and vice versa)
Convert from standard form (Ax+By = C) to slope-intercept form (y = mx+b)


\"1x%2B3y=6\" Start with the given equation


\"1x%2B3y-1x=6-1x\" Subtract 1x from both sides


\"3y=-1x%2B6\" Simplify


\"%283y%29%2F%283%29=%28-1x%2B6%29%2F%283%29\" Divide both sides by 3 to isolate y


\"y+=+%28-1x%29%2F%283%29%2B%286%29%2F%283%29\" Break up the fraction on the right hand side


\"y+=+%28-1%2F3%29x%2B2\" Reduce and simplify


The original equation \"1x%2B3y=6\" (standard form) is equivalent to \"y+=+%28-1%2F3%29x%2B2\" (slope-intercept form)


The equation \"y+=+%28-1%2F3%29x%2B2\" is in the form \"y=mx%2Bb\" where \"m=-1%2F3\" is the slope and \"b=2\" is the y intercept.



\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now let's find the equation of the line that is perpendicular to \"y=%28-1%2F3%29x%2B2\" which goes through (7,-8)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

\n" ); document.write( "
\n" ); document.write( " Remember, any two perpendicular lines are negative reciprocals of each other. So if you're given the slope of \"-1%2F3\", you can find the perpendicular slope by this formula:
\n" ); document.write( "
\n" ); document.write( " \"m%5Bp%5D=-1%2Fm\" where \"m%5Bp%5D\" is the perpendicular slope
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"m%5Bp%5D=-1%2F%28-1%2F3%29\" So plug in the given slope to find the perpendicular slope
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"m%5Bp%5D=%28-1%2F1%29%283%2F-1%29\" When you divide fractions, you multiply the first fraction (which is really \"1%2F1\") by the reciprocal of the second
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"m%5Bp%5D=3%2F1\" Multiply the fractions.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So the perpendicular slope is \"3\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So now we know the slope of the unknown line is \"3\" (its the negative reciprocal of \"-1%2F3\" from the line \"y=%28-1%2F3%29%2Ax%2B2\").\n" ); document.write( "Also since the unknown line goes through (7,-8), we can find the equation by plugging in this info into the point-slope formula
\n" ); document.write( "
\n" ); document.write( " Point-Slope Formula:
\n" ); document.write( "
\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y%2B8=3%2A%28x-7%29\" Plug in \"m=3\", \"x%5B1%5D=7\", and \"y%5B1%5D=-8\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y%2B8=3%2Ax-%283%29%287%29\" Distribute \"3\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y%2B8=3%2Ax-21\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=3%2Ax-21-8\"Subtract \"-8\" from both sides to isolate y
\n" ); document.write( "
\n" ); document.write( " \"y=3%2Ax-29\" Combine like terms
\n" ); document.write( "
\n" ); document.write( " So the equation of the line that is perpendicular to \"y=%28-1%2F3%29%2Ax%2B2\" and goes through (\"7\",\"-8\") is \"y=3%2Ax-29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So here are the graphs of the equations \"y=%28-1%2F3%29%2Ax%2B2\" and \"y=3%2Ax-29\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " graph of the given equation \"y=%28-1%2F3%29%2Ax%2B2\" (red) and graph of the line \"y=3%2Ax-29\"(green) that is perpendicular to the given graph and goes through (\"7\",\"-8\")
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );