Algebra.Com's Answer #746652 by ikleyn(52781)  You can put this solution on YOUR website! . \n" );
document.write( "Solve the equation (y+5/y)^2 + 3(y+5/y)=4 ,using substitution u=y+5/y \n" );
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document.write( "When you introduce new variable u = , the original equation takes the form\r\n" );
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document.write( "u^2 + 3u - 4 = 0.\r\n" );
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document.write( "Factoring, you get\r\n" );
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document.write( "(u+4)*(u-1) = 0,\r\n" );
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document.write( "which gives you two roots u= -4 and u= 1.\r\n" );
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document.write( "Thus, now you need to solve two equations = -4 and = 1 to find possible solutions for \"y\".\r\n" );
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document.write( "1) = -4 <====> is equivalent to\r\n" );
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document.write( " = 0 <=====> is equivalent to\r\n" );
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document.write( " = 0 or = -1\r\n" );
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document.write( " which has no solutions in real numbers,\r\n" );
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document.write( " but has two solutions in complex numbers x= -2 + i and x= -2 -i. \r\n" );
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document.write( "2) = 1 <====> is equivalent to\r\n" );
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document.write( " = 0 <=====> is equivalent to\r\n" );
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document.write( " = 0 or = -4.75,\r\n" );
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document.write( " which has no solutions in real numbers,\r\n" );
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document.write( " but has two solutions in complex numbers x= and x= .\r\n" );
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document.write( "Answer. Your original equation has no solution/solutions in real numbers, but has 4 (four) solutions in complex numbers, listed above.\r\n" );
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document.write( "Solved and explained.\r \n" );
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