document.write( "Question 102544: solve by using the quadratic formula?\r
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Algebra.Com's Answer #74665 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"5x%5E2%2B5x=3\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"5x%5E2%2B5x-3=0\" Subtract 3 from both sides\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"5%2Ax%5E2%2B5%2Ax-3=0\" ( notice \"a=5\", \"b=5\", and \"c=-3\")\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%28+%285%29%5E2-4%2A5%2A-3+%29%29%2F%282%2A5%29\" Plug in a=5, b=5, and c=-3\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%28+25-4%2A5%2A-3+%29%29%2F%282%2A5%29\" Square 5 to get 25 \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%28+25%2B60+%29%29%2F%282%2A5%29\" Multiply \"-4%2A-3%2A5\" to get \"60\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%28+85+%29%29%2F%282%2A5%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%2885%29%29%2F10\" Multiply 2 and 5 to get 10\r
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\n" ); document.write( "\n" ); document.write( "So our answer is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%2885%29%29%2F10\" \r
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