document.write( "Question 1129874: 0° ≤ θ < 360°\r
\n" ); document.write( "\n" ); document.write( "2sin(θ)-sqrt3=0\r
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Algebra.Com's Answer #746627 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " $\"2sin%28theta%29-sqrt%283%29=0+\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"2sin%28theta%29=sqrt%283%29+\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"sin%28theta%29=sqrt%283%29%2F2+\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"theta=sin%5E-1%28sqrt%283%29%2F2+%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"theta=pi%2F3\"$ ...........(result in radians)\r
\n" ); document.write( "\n" ); document.write( " $\"theta=60\"$ °\r
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