document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1129950>Question 1129950</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A number of two-digit has 3 for its unit digit and the sum of the digit is 2/11 of the number itself. The number is </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #746581 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=746581\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The number can be written as 10t + u, where t is the tens place, u is the units place<BR>\n" );
document.write( "Given: u = 3 and sum of digits = 2/11 of the number<BR>\n" );
document.write( "(2/11)(10t + 3) = t + 3<BR>\n" );
document.write( "Solve for t:<BR>\n" );
document.write( "(9/11)t = 33/11 - 6/11 = 27/11<BR>\n" );
document.write( "t = 3<BR>\n" );
document.write( "Check: (2/11)33 = 2*3 = 6 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );