document.write( "Question 102641This question is from textbook
\n" ); document.write( ": Please help. I don't even know where to begin with this problem:\r
\n" ); document.write( "\n" ); document.write( "Graph the inequality and shade in the correct area of the graph:\r
\n" ); document.write( "\n" ); document.write( "x + 3y is equal to or greater than -2\r
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Algebra.Com's Answer #74658 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
In order to graph \"x%2B3y%3E=-2\", we need to graph the equation \"x%2B3y=-2\" (just replace the inequality sign with an equal sign).
\n" ); document.write( "So lets graph the line \"x%2B3y=-2\" (note: if you need help with graphing, check out this solver)\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-20%2C+20%2C+-20%2C+20%2C+-%281%2F3%29x-%282%2F3%29%29+\" graph of \"x%2B3y=-2\" \r
\n" ); document.write( "\n" ); document.write( "Now lets pick a test point, say (0,0). Any point will work, (just make sure the point doesn't lie on the line) but this point is the easiest to work with. Now evaluate the inequality \"x%2B3y%3E=-2\" with the test point\r
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\n" ); document.write( "\n" ); document.write( "Substitute (0,0) into the inequality\r
\n" ); document.write( "\n" ); document.write( "\"%280%29%2B3%280%29%3E=-2\" Plug in \"x=0\" and \"y=0\"\r
\n" ); document.write( "\n" ); document.write( "\"0%3E=-2\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "Since this inequality is true, we simply shade the entire region that contains (0,0)\r
\n" ); document.write( "\n" ); document.write( " Graph of \"x%2B3y%3E=-2\" with the boundary (which is the line \"x%2B3y=-2\" in red) and the shaded region (in green)
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