document.write( "Question 1129909: Last year, at Haven's Pond Car Dealership, for a particular model of BMW, Jeep, and Toyota, one could purchase all three cars for a total of $140,000. This year, due to inflation, the same cars would cost $151,830. The cost of the BMW increased by 9%, the Jeep by 5%, and the Toyota by 11%. If the price of last year's Jeep was $7,000 less than the price of last year's BMW, what was the price of each of the three cars last year? (Round your answers to the nearest integer.) \n" ); document.write( "
Algebra.Com's Answer #746568 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Let last year's prices be B, J, and T. The sum of the prices last year was $140,000:

\n" ); document.write( "(1) \"B+%2B+J+%2B+T+=+140000\"

\n" ); document.write( "The BMW increased in price by 9%, the Jeep by 5%, and the Toyota by 11%. The sum of the prices this year is $151,830:

\n" ); document.write( "(2) \"1.09B+%2B+1.05J+%2B+1.11T+=+151380\"

\n" ); document.write( "The price of last year's Jeep was $7000 less than the price of last year's BMW:

\n" ); document.write( "(3) \"J+=+B-7000\"

\n" ); document.write( "With the ugly decimal coefficients, I would definitely use matrices on a graphing calculator to solve the problem. The first two equations are in the required form for most graphing calculators; the third equation needs to be put in that form. The matrix would be

\n" ); document.write( "\"matrix%283%2C4%2C1%2C1%2C1%2C1400000%2C1.09%2C1.05%2C1.11%2C151830%2C1%2C-1%2C0%2C7000%29\"

\n" ); document.write( "You can do the calculations....

\n" ); document.write( "Note the answers are nice whole numbers....
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