document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1129911>Question 1129911</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Assume &#945; is opposite side a, &#946; is opposite side b, and &#947; is opposite side c. If possible, solve the triangle for the unknown side. Round to the nearest tenth. (If not possible, enter IMPOSSIBLE.) <BR>\n" );
document.write( "&#946; = 56.8°,<BR>\n" );
document.write( "a = 10.2,<BR>\n" );
document.write( "c = 15.3\r<BR>\n" );
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document.write( "b=?\r<BR>\n" );
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document.write( "thanks in advance </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #746565 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13215)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=746565\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Two sides and the included angle, as is given in this case, always produces a single triangle.  The length of the third side is given by the law of cosines.<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E2+=+a%5E2%2Bc%5E2-2ac%2Asin%28B%29 ALIGN=MIDDLE  ALT=\"b%5E2+=+a%5E2%2Bc%5E2-2ac%2Asin%28B%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "You can do the calculations as easily as we can.... </SPAN>\n" );
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