document.write( "Question 1129935: Show every step. This is a proof.
\n" ); document.write( "If \"log_b%28x%29=%281%2F2%29log_b%28v%2B3%29\", show that \"x+=+%28b%5E3%29+sqrt%28v%29\"
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Algebra.Com's Answer #746560 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The statement is not true; so it can't be proved.

\n" ); document.write( "Use \"nice\" numbers to find a counterexample: b=2, v=13. Then the right side of the given equation evaluates to

\n" ); document.write( "\"%281%2F2%29log_2%2813%2B3%29+=+%281%2F2%29log_2%2816%29+=+%281%2F2%29%284%29+=+2\"

\n" ); document.write( "Then the equation says the expression on the left, log_2(x), is equal to 2. So

\n" ); document.write( "log_2(x)=2 --> x = 2^2 = 4.

\n" ); document.write( "But the statement we are trying to prove is x = (b^3)^sqrt(v), and it is certainly not true that

\n" ); document.write( "4 = (2^3)(sqrt(13).

\n" ); document.write( "Note that if you show the given equation correctly, a proof is possible....
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