document.write( "Question 1129938: Show all work. Find the exact value of n.
\n" ); document.write( "\"3%5E2002+-+3%5E2001+%2B+3%5E2000+-+3%5E1999+=+n%283%5E1999%29\"
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Algebra.Com's Answer #746555 by greenestamps(13334)\"\" \"About 
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\n" ); document.write( "Factor 3^1999 out of each term on the left....

\n" ); document.write( "\"3%5E2002+-+3%5E2001+%2B+3%5E2000+-+3%5E1999\" =

\n" ); document.write( "\"%283%5E3%29%2A3%5E1999+-+%283%5E2%29%2A3%5E1999+%2B+3%2A3%5E1999+-+1%2A3%5E1999\" =

\n" ); document.write( "\"%2827-9%2B3-1%29%2A3%5E1999\" =

\n" ); document.write( "\"20%283%5E1999%29\"

\n" ); document.write( "ANSWER: n = 20
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