document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1129898>Question 1129898</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the lengths of the missing sides if side a is opposite angle A, side b is opposite angle B, and side c is the hypotenuse. <BR>\n" );
document.write( "cos(B) = 4/5, a = 38\r<BR>\n" );
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document.write( "b=?<BR>\n" );
document.write( "c=?\r<BR>\n" );
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document.write( "please help... Ive tried this problem more than once and got different answers.. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #746525 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=746525\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Find the lengths of the missing sides if side a is opposite angle A, side b is opposite angle B, and side c is the hypotenuse. <BR>\n" );
document.write( "cos(B) = 4/5, a = 38<BR>\n" );
document.write( "cos(B) = a/c<BR>\n" );
document.write( "4/5 = 38/c<BR>\n" );
document.write( "c = 38/(4/5) = 47.5<BR>\n" );
document.write( "------<BR>\n" );
document.write( "b^2 = c^2-a^2<BR>\n" );
document.write( "b^2 = 47.5^2-38^2<BR>\n" );
document.write( "b^2 = 812.25<BR>\n" );
document.write( "b = 28.5<BR>\n" );
document.write( "-------------  <BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );