document.write( "Question 1129897: There were 30 nickels,dimes,and pennies, and their value was $1.35. If there were twice as many pennies as dimes, how many of each kind were there?
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Algebra.Com's Answer #746522 by stanbon(75887)\"\" \"About 
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There were 30 nickels,dimes,and pennies, and their value was $1.35. If there were twice as many pennies as dimes, how many of each kind were there?
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\n" ); document.write( "Equations:
\n" ); document.write( "p + n + d = 30 coins
\n" ); document.write( "p + 5n + 10d = 135 cent
\n" ); document.write( "p = 2d
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\n" ); document.write( "Substitute for \"p\"::
\n" ); document.write( "n + 3d = 30
\n" ); document.write( "5n+12d = 135
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\n" ); document.write( "Modify and solve for \"d\"::
\n" ); document.write( "5n + 15d = 150
\n" ); document.write( "5n + 12d = 135
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\n" ); document.write( "Subtract and solve for \"d\"::
\n" ); document.write( "3d = 15
\n" ); document.write( "d = 5 (# of dimes)
\n" ); document.write( "p = 2d = 10 (# of pennies)
\n" ); document.write( "n + 3*5 = 30
\n" ); document.write( "n = 15 (# of nickels)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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