document.write( "Question 1129876: A compound with a molecular weight of 98 g/mole was determined to be composed of 24.49% carbon,4.08% hydrogen with the remainder composed of chlorine with the remainder composed of chlorine. What is the empiricism formula and molecular formula ? \n" ); document.write( "
Algebra.Com's Answer #746511 by josgarithmetic(39618)\"\" \"About 
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\n" ); document.write( "Compound with molecular weight 98 grams/mole
\n" ); document.write( "The percentage difference would be that of Chlorine; being 71.43% Cl.\r
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\n" ); document.write( "\n" ); document.write( "amu data taken from https://en.wikipedia.org/wiki/Periodic_table\r
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\n" ); document.write( "\n" ); document.write( "Chlorine moles
\n" ); document.write( "\"71.43%2F35%2F45\"\r
\n" ); document.write( "\n" ); document.write( "2.01495 moles Cl\r
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\n" ); document.write( "\n" ); document.write( "Carbon moles
\n" ); document.write( "\"24.49%2F12.011\"\r
\n" ); document.write( "\n" ); document.write( "2,03896 moles C\r
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\n" ); document.write( "\n" ); document.write( "Hydrogen moles
\n" ); document.write( "\"4.08%2F1.008\"\r
\n" ); document.write( "\n" ); document.write( "4.047 moles H\r
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\n" ); document.write( "\n" ); document.write( "Not absolutely the best estimate but close enough,\r
\n" ); document.write( "\n" ); document.write( "\"C%5B2%5DH%5B4%5DCl%5B2%5D\", with a calculated formula weight of
\n" ); document.write( "\"2%2A12.011%2B4%2A1.008%2B2%2A35.45=98.95\", grams per mole, not too far off from the given quantity
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