document.write( "Question 1129845: The half-life of element X is 13.25 minutes, if the orginal of the sample is 2.36 kg, how long will it take in HOURS for the remaining mass to be 12.0 grams ? \n" ); document.write( "
Algebra.Com's Answer #746476 by ankor@dixie-net.com(22740)\"\" \"About 
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The half-life of element X is 13.25 minutes,
\n" ); document.write( " if the original of the sample is 2.36 kg,
\n" ); document.write( " how long will it take in HOURS for the remaining mass to be 12.0 grams ?
\n" ); document.write( ":
\n" ); document.write( "The radio active decay formula
\n" ); document.write( "A = Ao*2^(-t/h) where
\n" ); document.write( "A = remaining amt after t time
\n" ); document.write( "Ao = initial amt
\n" ); document.write( "t = time of decay
\n" ); document.write( "h = half-life of substance
\n" ); document.write( ":
\n" ); document.write( "Change 2.36 kg to 2360 grams
\n" ); document.write( "2360*2^(-t/13.25} = 12
\n" ); document.write( "2^(-t/13.25) = \"12%2F2360\"
\n" ); document.write( "\"ln%282%5E%28-t%2F13.25%29%29\" = \"ln%2812%2F2360%29\"
\n" ); document.write( "the log equiv of exponents
\n" ); document.write( "\"-t%2F13.25\"ln(2) = \"ln%2812%2F2360%29\"
\n" ); document.write( "\"-t%2F13.25\" = \"ln%2812%2F2360%29%2Fln%282%29\"
\n" ); document.write( "Using our calc
\n" ); document.write( "\"-t%2F13.25\" = -7.61961
\n" ); document.write( "t = -13.25 * -7.61961
\n" ); document.write( "t = 100.9598 ~ 101 minutes
\n" ); document.write( "which is
\n" ); document.write( "101/60 = 1.68 hrs
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