document.write( "Question 1129845: The half-life of element X is 13.25 minutes, if the orginal of the sample is 2.36 kg, how long will it take in HOURS for the remaining mass to be 12.0 grams ? \n" ); document.write( "
Algebra.Com's Answer #746476 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The half-life of element X is 13.25 minutes, \n" ); document.write( " if the original of the sample is 2.36 kg, \n" ); document.write( " how long will it take in HOURS for the remaining mass to be 12.0 grams ? \n" ); document.write( ": \n" ); document.write( "The radio active decay formula \n" ); document.write( "A = Ao*2^(-t/h) where \n" ); document.write( "A = remaining amt after t time \n" ); document.write( "Ao = initial amt \n" ); document.write( "t = time of decay \n" ); document.write( "h = half-life of substance \n" ); document.write( ": \n" ); document.write( "Change 2.36 kg to 2360 grams \n" ); document.write( "2360*2^(-t/13.25} = 12 \n" ); document.write( "2^(-t/13.25) = \n" ); document.write( " \n" ); document.write( "the log equiv of exponents \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Using our calc \n" ); document.write( " \n" ); document.write( "t = -13.25 * -7.61961 \n" ); document.write( "t = 100.9598 ~ 101 minutes \n" ); document.write( "which is \n" ); document.write( "101/60 = 1.68 hrs \n" ); document.write( " \n" ); document.write( " |