document.write( "Question 1129820: The number of pending corporate fraud cases stood at 545 at the begining of 2008 (t=0)
\n" ); document.write( "and was approximately linear.
\n" ); document.write( "a. Derive an equation of the line passing through the points A (0.545) and B (4,726).
\n" ); document.write( "b. Plot the line with the equation found in part a .
\n" ); document.write( "c. Use the equation found in part (a) to estimate the number of pending corporate fraud cases at the beginning of 2014.
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Algebra.Com's Answer #746438 by stanbon(75887)\"\" \"About 
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The number of pending corporate fraud cases stood at 545 at the begining of 2008 (t=0)
\n" ); document.write( "and was approximately linear.
\n" ); document.write( "a. Derive an equation of the line passing through the points A (0,545) and B (4,726).
\n" ); document.write( "c = mt + k
\n" ); document.write( "slope = m = (726-545)/(4-0) = 45.25
\n" ); document.write( "c(0) = 545
\n" ); document.write( "Equation:: c = 45.25t + 545
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\n" ); document.write( "b. Plot the line with the equation found in part a .
\n" ); document.write( "Note:: If t = 0 for 2008, t = 6 for 2014
\n" ); document.write( "\"graph%280%2C10%2C0%2C850%2C45.25x%2B545%29\"
\n" ); document.write( "c. Use the equation found in part (a) to estimate the number of pending corporate fraud cases at the beginning of 2014.
\n" ); document.write( "Ans::c(6) = 816.53
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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