document.write( "Question 1129805: Andrea and Brad live 18km apart. Brad walked towards Andrea's house at 1.5km/h. Four hours later, Andrea leaves home and walks towards Brad's house at 4.5km/h. Find when and where they meet. \n" ); document.write( "
Algebra.Com's Answer #746428 by ankor@dixie-net.com(22740)\"\" \"About 
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Andrea and Brad live 18km apart.
\n" ); document.write( " Brad walked towards Andrea's house at 1.5km/h.
\n" ); document.write( "Four hours later, Andrea leaves home and walks towards Brad's house at 4.5km/h.
\n" ); document.write( " Find when and where they meet.
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\n" ); document.write( "let t = B's walking time
\n" ); document.write( "A left four hrs later, therefore
\n" ); document.write( "(t-4) = A's walking time
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\n" ); document.write( "When they meet, the total of their distances will be 18 km
\n" ); document.write( "write a distance equation; dist = speed * time
\n" ); document.write( "1.5t + 4.5(t-4) = 18
\n" ); document.write( "1.5t + 4.5t - 18 = 18
\n" ); document.write( "6t = 18 + 18
\n" ); document.write( "6t = 36
\n" ); document.write( "t = 36/6
\n" ); document.write( "t = 6 hrs is Brad's walking time when they meet
\n" ); document.write( "Andrea will have walked 4 hrs less or 2 hrs
\n" ); document.write( ":
\n" ); document.write( "Find the point from Brad's house where they meet
\n" ); document.write( "1.5(6) = 9 mi or half way
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "Check this, B walked 9 mi and A walked 4.5(2), 9 mi, a total of 18 mi
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