document.write( "Question 102616: 5x to the 2 power +9x+1=0 \n" ); document.write( "
Algebra.Com's Answer #74641 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let's use the quadratic formula to solve for x:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"5%2Ax%5E2%2B9%2Ax%2B1=0\" ( notice \"a=5\", \"b=9\", and \"c=1\")\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-9+%2B-+sqrt%28+%289%29%5E2-4%2A5%2A1+%29%29%2F%282%2A5%29\" Plug in a=5, b=9, and c=1\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-9+%2B-+sqrt%28+81-4%2A5%2A1+%29%29%2F%282%2A5%29\" Square 9 to get 81 \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-9+%2B-+sqrt%28+81%2B-20+%29%29%2F%282%2A5%29\" Multiply \"-4%2A1%2A5\" to get \"-20\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-9+%2B-+sqrt%28+61+%29%29%2F%282%2A5%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-9+%2B-+sqrt%2861%29%29%2F10\" Multiply 2 and 5 to get 10\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-9+%2B+sqrt%2861%29%29%2F10\" or \"x+=+%28-9+-+sqrt%2861%29%29%2F10\"\r
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\n" ); document.write( "\n" ); document.write( "Now break up the fraction\r
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\n" ); document.write( "\n" ); document.write( "\"x=-9%2F10%2Bsqrt%2861%29%2F10\" or \"x=-9%2F10-sqrt%2861%29%2F10\"\r
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\n" ); document.write( "\n" ); document.write( "So these expressions approximate to\r
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\n" ); document.write( "\n" ); document.write( "\"x=-0.118975032409335\" or \"x=-1.68102496759067\"\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"x=-0.118975032409335\" or \"x=-1.68102496759067\"\r
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\n" ); document.write( "\n" ); document.write( "Notice when we graph \"5%2Ax%5E2%2B9%2Ax%2B1\", we get:\r
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\n" ); document.write( "\n" ); document.write( "when we use the root finder feature on a calculator, we find that \"x=-0.118975032409335\" and \"x=-1.68102496759067\".So this verifies our answer
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