document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=14934>Question 14934</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 133. Four times the smaller of the two numbers equals three times the greater number. Find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7464 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7464\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the smaller number and y the bigger number.<BR>\n" );
document.write( " we have x+y=133.......(1)<BR>\n" );
document.write( " and 4*x=3*y ..........(2)<BR>\n" );
document.write( "multiplying (1) with 3 throught we get 3*x+3*y=3*133...substituting 3*y=4*x in this we get 3*x+4*x=399  <BR>\n" );
document.write( "    7*x=399<BR>\n" );
document.write( "    x=399/7=57<BR>\n" );
document.write( "    since 4*x=3*y=4*57<BR>\n" );
document.write( "       y=4*57/3=4*19=76<BR>\n" );
document.write( "  hence x=57 and y=76.... </SPAN>\n" );
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