document.write( "Question 1129698: The length of a conference room is one and a half times its width.A carpet is placed in the center of the room.The length of the carpet is twice it width. This leaves a 3m wide border around the edges of the carpet.Find the area of the carpet. \n" ); document.write( "

Algebra.Com's Answer #746355 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+w+\"$ = the width of the room
\n" ); document.write( " $\"+%283%2F2%29%2Aw+\"$ = the length of the room
\n" ); document.write( " $\"+w+-+2%2A3+=+w+-+6+\"$ is the width of the carpet
\n" ); document.write( " $\"+%283%2F2%29%2Aw+-+2%2A3+=+%283%2F2%29%2Aw+-+6+\"$ is the length of the carpet
\n" ); document.write( "--------------------------------------------------------------------
\n" ); document.write( "I can now say:
\n" ); document.write( " $\"+%283%2F2%29%2Aw+-+6+=+2%2A%28+w+-+6+%29+\"$
\n" ); document.write( " $\"+3w+-+12+=+4w+-+24+\"$
\n" ); document.write( " $\"+w+=+12+\"$
\n" ); document.write( "-------------------------
\n" ); document.write( " $\"+w+-+6+=+12+-+6+\"$
\n" ); document.write( " $\"+w+-+6+=+6+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+%283%2F2%29%2A12+-+6+=+18+-+6+\"$
\n" ); document.write( " $\"+%283%2F2%29%2A12+-+6+=+12+\"$
\n" ); document.write( "-----------------------------
\n" ); document.write( "The area of the rug is:
\n" ); document.write( " $\"+6%2A12+=+72+\"$
\n" ); document.write( "72 m2
\n" ); document.write( "-----------------------------
\n" ); document.write( "check: the dimensions of the room are:
\n" ); document.write( " $\"+w+=+12+\"$ and
\n" ); document.write( " $\"+%283%2F2%29%2A12+=+18+\"$
\n" ); document.write( " $\"+12+-+2%2A3+=+6+\"$
\n" ); document.write( " $\"+18+-+2%2A3+=+12+\"$
\n" ); document.write( "OK \n" ); document.write( "

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