document.write( "Question 1129747: The O'Connors own a small janitorial service. John requires 1/4 hour more time to clean the Moose club by himself than Chris does working by herself. If together they can clean the club in 4 ​hours, find the time required by each to clean the club.\r
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Algebra.Com's Answer #746353 by josmiceli(19441)\"\" \"About 
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Let \"+t+\" = time in hrs required by Chris
\n" ); document.write( "to clean the Moose club
\n" ); document.write( "Add their rates of cleaning to get rate
\n" ); document.write( "working together
\n" ); document.write( "\"+1%2F%28%285%2F4%29%2At%29+%2B+1%2Ft+=+1%2F4+\"
\n" ); document.write( "\"+4%2F%285t%29+%2B+1%2Ft+=+1%2F4+\"
\n" ); document.write( "Multiply both sides by \"+5%2A4t+\"
\n" ); document.write( "\"+16+%2B+20+=+5t+\"
\n" ); document.write( "\"+5t+=+36+\"
\n" ); document.write( "\"+t+=+7.2+\" hrs
\n" ); document.write( "and
\n" ); document.write( "\"+%285%2F4%29%2A7.2+=+9+\" hrs
\n" ); document.write( "Chris takes 7 hrs 12 min
\n" ); document.write( "John takes 9 hrs
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\n" ); document.write( "check:
\n" ); document.write( "\"+1%2F9+%2B+1%2F7.2+=+.25+\"
\n" ); document.write( "\"+.11111+%2B+.13888+=+.25+\"
\n" ); document.write( "\"+.25+=+.25+\"
\n" ); document.write( "OK
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