document.write( "Question 1129762: I need to graph this line using the slope and y-intercept\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Y= 3x + 3
\n" ); document.write( "

Algebra.Com's Answer #746349 by math_helper(2461)\"\" \"About 
You can put this solution on YOUR website!
Slope-intercept form of a line:
\r
\n" ); document.write( "\n" ); document.write( " y = mx + b

\n" ); document.write( "where:
\n" ); document.write( "m = slope
\n" ); document.write( "b = y-intercept
\r
\n" ); document.write( "\n" ); document.write( "y = 3x + 3 clearly intercepts the y-axis at y=3 (just set x=0 to see this). This is the point (0,3). Pick any other value for x and then you will have a 2nd point: say x=2, y = 3(2) + 3 = 9. So (2,9) is another point on the line. Plot the two points then draw a straight line through them, that is y = 3x+3. \r
\n" ); document.write( "\n" ); document.write( "
\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28300%2C300%2C+-6%2C12%2C-6%2C12+%2C+y=3x%2B3%29+\"
\n" ); document.write( "
\n" );