document.write( "Question 1129746: Data collected on the workforce at your company yielded a mean height of 67.25 inches and a standard deviation of 2.5 inches. Calculate the 5th percentile, the 75th percentile, and the 90th percentile for your workforce. \n" ); document.write( "
Algebra.Com's Answer #746344 by stanbon(75887) ![]() You can put this solution on YOUR website! Data collected on the workforce at your company yielded a mean height of 67.25 inches and a standard deviation of 2.5 inches. Calculate the 5th percentile, the 75th percentile, and the 90th percentile for your workforce. \n" ); document.write( "--- \n" ); document.write( "5th %ile:: \n" ); document.write( "Find invNorm(0.05) = -1.6449 \n" ); document.write( "5th %ile = -1.6449*2.5+67.25 \n" ); document.write( "--------------- \n" ); document.write( "75th %ile \n" ); document.write( "Find invNorm(0.75) = 0.6745 \n" ); document.write( "75th %ile = 0.6745*2.5+67.25 \n" ); document.write( "------ \n" ); document.write( "You should be able to figure out the 90th %ile: it's 70.45 \n" ); document.write( "------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |