document.write( "Question 1129746: Data collected on the workforce at your company yielded a mean height of 67.25 inches and a standard deviation of 2.5 inches. Calculate the 5th percentile, the 75th percentile, and the 90th percentile for your workforce. \n" ); document.write( "
Algebra.Com's Answer #746344 by stanbon(75887)\"\" \"About 
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Data collected on the workforce at your company yielded a mean height of 67.25 inches and a standard deviation of 2.5 inches. Calculate the 5th percentile, the 75th percentile, and the 90th percentile for your workforce.
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\n" ); document.write( "5th %ile::
\n" ); document.write( "Find invNorm(0.05) = -1.6449
\n" ); document.write( "5th %ile = -1.6449*2.5+67.25
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\n" ); document.write( "75th %ile
\n" ); document.write( "Find invNorm(0.75) = 0.6745
\n" ); document.write( "75th %ile = 0.6745*2.5+67.25
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\n" ); document.write( "You should be able to figure out the 90th %ile: it's 70.45
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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