document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1129706>Question 1129706</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Convert the equation 2x-y+2=0 to polar form. then solve the resulting equation for r. i would really appreciate it if you can please help me i would really appreciate thank you.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #746340 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=746340\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Convert the equation 2x-y+2=0 to polar form. then solve the resulting equation for r. i would really appreciate it if you can please help me i would really appreciate thank you.<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Conversion from rectangular to polar::<BR>\n" );
document.write( "x = r*cos(t)<BR>\n" );
document.write( "y = 4sin(t)<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Substitute to get::<BR>\n" );
document.write( "2(r*cos(t)) - r*sin(t) = -2<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "r = -2/[2cos(t)-sin(t)]<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "-------  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );