document.write( "Question 102440This question is from textbook Intermediate Algebra
\n" ); document.write( ": (x^3+8)/(x^2-2x+4) \n" ); document.write( "
Algebra.Com's Answer #74632 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
:
\n" ); document.write( "\"%28x%5E3%2B8%29%2F%28x%5E2-2x%2B4%29\"
\n" ); document.write( ":
\n" ); document.write( "Note that the numerator can be factored as the \"sum of cubes\"
\n" ); document.write( "And one of the these factors is that same as the denominator, so they cancel\r
\n" ); document.write( "\n" ); document.write( "\"%28%28x%2B2%29%28x%5E2+-+2x+%2B+4%29%29%2F%28x%5E2-2x%2B4%29\" = (x+2)
\n" ); document.write( "
\n" ); document.write( "
\n" );