document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1129724>Question 1129724</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Theresa Morgan, a chemist, has a 25% hydrochloric acid solution and a 55% hydrochloric acid solution. How many liters of each should she mix to get 465 liters of a hydrochloric acid solution with a 45% acid concentration? \r<BR>\n" );
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document.write( "___ liters of 25% H   <BR>\n" );
document.write( "____ liters of 55% H  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #746301 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=746301\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One way is to note that 45% is 2/3 of the way between 25% and 55%, so twice as much of the 55% will be used.\r<BR>\n" );
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document.write( "Or, <BR>\n" );
document.write( "x at 25%<BR>\n" );
document.write( "465-x at 55%<BR>\n" );
document.write( ".25x+.55(465-x)=465*.45=209.25<BR>\n" );
document.write( ".25x+255.75-.55x=209.25<BR>\n" );
document.write( "-.30x=-46.50<BR>\n" );
document.write( "x=155 liters<BR>\n" );
document.write( "465-x=310 liters, twice as much. </SPAN>\n" );
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