document.write( "Question 1129604: In a program designed to help patients stop smoking,
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document.write( "195
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document.write( "195 patients were given sustained care, and
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document.write( "83.6
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document.write( "83.6% of them were no longer smoking after one month. Use a
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document.write( "0.01
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document.write( "0.01 significance level to test the claim that
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document.write( "80
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document.write( "80% of patients stop smoking when given sustained care. \n" );
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Algebra.Com's Answer #746262 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Assuming random sample, etc., this is a one sample proportion test \n" ); document.write( "Ho: 80% stop \n" ); document.write( "Ha: some other number stop \n" ); document.write( "test statistic is a z and critical value is |z|>2.576 \n" ); document.write( "z=(p hat-p)/sqrt((p*(1-p)/n)' sqrt term is sqrt(.8*.2/195)=0.0286 \n" ); document.write( "z=0.036/0.0286=1.26 \n" ); document.write( "Fail to reject Ho; insufficient evidence to reject Ho \n" ); document.write( " |