document.write( "Question 1129650: Amy invests $1500 in one account and $1900 in an account paying 3 % higher interest. At the end of one year she had earned $261 in interest. At what rates did she invest?\r
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document.write( "1500 invested at -
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document.write( "1900 invested at- \n" );
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Algebra.Com's Answer #746257 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! interest for 1500 is x \n" ); document.write( "interest for 1900 is x+3 \n" ); document.write( "1500*x/100=15x \n" ); document.write( "1900*(x+3)/100=19x+57 \n" ); document.write( "that sum is 261 \n" ); document.write( "34x=204 \n" ); document.write( "x=6% for $1500=$90 \n" ); document.write( "X+3 is 9% for $1900=$171 \n" ); document.write( " |