document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1129665>Question 1129665</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For g(x)=x^3-6x^2-13x+42:<BR>\n" );
document.write( "a. Prove x-2 is a factor (by using the remainder theorem).<BR>\n" );
document.write( "b. Find the other factors.\r<BR>\n" );
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document.write( "Here is what I have done so far:<BR>\n" );
document.write( "x^3-6x^2-13x+42<BR>\n" );
document.write( "     x-(2)<BR>\n" );
document.write( "2|1-6-13 42<BR>\n" );
document.write( " |2 -8  -42<BR>\n" );
document.write( "= 1 -4  -21 0\r<BR>\n" );
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document.write( "1x^2+4x-21<BR>\n" );
document.write( "x^2-4x-21= 0 Which my professor said was correct for part A.\r<BR>\n" );
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document.write( "So for B I put: There are no factors because part A is 0 and got that wrong. What did I do wrong?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #746229 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=746229\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "Your synthetic division process demonstrated the following fact:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ x^3\ -\ 6x^2\ -\ 13x\ +\ 42\ =\ (x\ -\  2)(x^2\ -\ 4x\ -\ 21)\">\r<BR>\n" );
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document.write( "I don't know where you got the idea that \"Part A is 0\".  The <i>remainder</i> resulting from the synthetic division in Part A is, indeed, zero, but that is simply the indicator that the divisor is a zero of the dividend function and that the quotient is the set of coefficients for the other factor. So:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ x^2\ -\ 4x\ -\ 21\">\r<BR>\n" );
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document.write( "is a factor of the original function.  However, you aren't done yet because the quadratic is factorable into, you guessed it, two factors.  I'll leave that part up to you.<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi}\ +\ 1\ =\ 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \ \\r\"> </SPAN>\n" );
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