document.write( "Question 1129654: My mom’s clock is running fast one second per minute and my dad’s clock is running
\n" ); document.write( "slow one second per minute. When I left, their clocks were the same and I returned
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Algebra.Com's Answer #746225 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
1 sec / min = 5 sec / 5 min
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\n" ); document.write( "I will compare each clock with a 3rd clock
\n" ); document.write( "which is running on time. Then I will see
\n" ); document.write( "when the 2 original clocks are 1 min apart
\n" ); document.write( "I will start when all 3 clocks are at 12:00
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\n" ); document.write( "(1) = on time clock
\n" ); document.write( "(2) = 1 sec/min slow clock
\n" ); document.write( "(3) = 1 sec/min fast clock
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\n" ); document.write( "(1) - - - - - (2) - - - - - (3) - - - - - - - - - difference
\n" ); document.write( "12:00 - - 12:00:00 - - - 12:00:00 - - - - - 0 sec
\n" ); document.write( "12:05 - - 12:04:55 - - - 12:05:05 - - - - - 10 sec
\n" ); document.write( "12:10 - - 12:09:50 - - - 12:10:10 - - - - - - 20 sec
\n" ); document.write( "12:15 - - 12:14:45 - - - 12:15:15 - - - - - - 30 sec
\n" ); document.write( "12:20 - - 12:19:40 - - - 12:20:20 - - - - - - 40 sec
\n" ); document.write( "12:25 - - 12:24:35 - - - 12:25:25 - - - - - - 50 sec
\n" ); document.write( "12:30 - - 12:29:30 - - - 12:30:30 - - - - - - 60 sec ( 1 min )
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\n" ); document.write( "In a half-hour ( 12:30 ), the 2 clocks show 1 min difference
\n" ); document.write( "Another way to look at it is that the difference between them
\n" ); document.write( "1 sec / min + 1 sec/min = 2 sec/min
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\n" ); document.write( "2 sec/min = 60 sec / 30 min\r
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