document.write( "Question 1129657: Area and parameter of rectangle is 6000 and 340 then length of parameters
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Algebra.Com's Answer #746223 by MathLover1(20855)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Area of rectangle is \"6000\": \r
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\n" ); document.write( "\n" ); document.write( "\"L%2AW=6000\"\r
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\n" ); document.write( "\n" ); document.write( "\"W=6000%2FL\"........eq.1\r
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\n" ); document.write( "\n" ); document.write( "and perimeter is \"340+\":\r
\n" ); document.write( "\n" ); document.write( "\"2%28L%2BW%29=340\"\r
\n" ); document.write( "\n" ); document.write( "\"L%2BW=340%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"L%2BW=170\"\r
\n" ); document.write( "\n" ); document.write( "\"W=170-L\".......eq.2\r
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\n" ); document.write( "\n" ); document.write( "from eq.1 and eq.2\r
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\n" ); document.write( "\n" ); document.write( "\"6000%2FL=170-L\"\r
\n" ); document.write( "\n" ); document.write( "\"6000=170L-L%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"L%5E2-170L%2B6000=0\"\r
\n" ); document.write( "\n" ); document.write( "\"L%5E2-120L-50L%2B6000=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28L%5E2-120L%29-%2850L-6000%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"L%28L-120%29-50%28L-120%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28L+-+120%29+%28L+-+50%29+=+0\"\r
\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "if \"%28L+-+120%29+=+0\"=>\"L=120\"
\n" ); document.write( "if \"+%28L+-+50%29+=+0\"=>\"L=50\"\r
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\n" ); document.write( "\n" ); document.write( "so, \"L=120\" or \"L=50\"\r
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\n" ); document.write( "\n" ); document.write( "then\r
\n" ); document.write( "\n" ); document.write( "\"W=170-L\"=>\"W=170-120\"=>\"W=50\"
\n" ); document.write( "\"W=170-L\"=>\"W=170-50\"=>\"W=120\" \r
\n" ); document.write( "\n" ); document.write( "=>\"W=50\" or \"W=120\" \r
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\n" ); document.write( "\n" ); document.write( "since length is greater than width, then length of rectangle is \"L=120\" and the width is \"W=50\" \r
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