document.write( "Question 1129655: substitution \r
\n" ); document.write( "\n" ); document.write( "x+3y=2
\n" ); document.write( "2x-y=1
\n" ); document.write( "

Algebra.Com's Answer #746216 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
substitution \r
\n" ); document.write( "\n" ); document.write( "x+3y=2
\n" ); document.write( "2x-y=1
\n" ); document.write( "==================
\n" ); document.write( "Solve the 2nd eqn for y, then sub for y in the 1st eqn.
\n" ); document.write( "
\n" ); document.write( "
\n" );