document.write( "Question 1129617: which has a greater effect on the surface area of a right circular cone, doubling the radius or doubling the height? \n" ); document.write( "

Algebra.Com's Answer #746199 by math_helper(2461) $\"\"$ $\"About$

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$\"+A+=+%28pi%29r%5E2+%2B+%28pi%29r%2Asqrt%28r%5E2%2Bh%5E2%29+\"$ \r
\n" ); document.write( "\n" ); document.write( "The first term is the area of the disk at the bottom, the 2nd term is the area of the slanted cone part.
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\n" ); document.write( "\n" ); document.write( "Even if we ignore the circular disk at the bottom, the exponent of r (2) is higher than that of h (1), so A is more sensitive to changes in r than h. Adding in the disk makes it even more sensitive to r.
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\n" ); document.write( "Ans: Doubling the radius has a greater effect on the surface area of a right circular cone. \r
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\n" ); document.write( "\n" ); document.write( "You can plug in values for r, h, compute a baseline A(r,h), then compute A(2r,h), then compute A(r,2h) and compare... \n" ); document.write( "

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