document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1129618>Question 1129618</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Explain how to construct a line segment with length square root of 13 cm? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #746193 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52781)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=746193\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .\r<BR>\n" );
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document.write( "13 = 9 + 4 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%5E2 ALIGN=MIDDLE  ALT=\"3%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%5E2 ALIGN=MIDDLE  ALT=\"2%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "Therefore,  &nbsp;<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2813%29 ALIGN=MIDDLE  ALT=\"sqrt%2813%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > &nbsp;is the length of the hypotenuse of the right angled triangle with the legs of &nbsp;3 &nbsp;and &nbsp;2 &nbsp;centimeters long.\r<BR>\n" );
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document.write( "    So, with a liner and a compass the construction is as follows.\r\n" );
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document.write( "    Draw a straight line.\r\n" );
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document.write( "    From the point A on the line, construct the segment AB on the line of the length 3 centimeters.\r\n" );
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document.write( "    Construct the perpendicular line to the straight line AB at the point B.\r\n" );
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document.write( "    On the perpendicular, construct the segment BC of the length 2 cm.\r\n" );
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document.write( "    Connect the point A and C by the liner.\r\n" );
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document.write( "    The segment AC is what you need.\r\n" );
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document.write( "Solved.\r<BR>\n" );
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document.write( "On basic operations in construction problems with a liner and a compass, see the lessons\r<BR>\n" );
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document.write( "&nbsp;&nbsp;&nbsp;&nbsp;- <A  rel=nofollow HREF=http://www.algebra.com/algebra/homework/Triangles/How-to-bisect-a-segment-using-a-compass-and-a-ruler.lesson>HOW TO bisect a segment using a compass and a ruler</A>\r<BR>\n" );
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document.write( "&nbsp;&nbsp;&nbsp;&nbsp;- <A  rel=nofollow HREF=http://www.algebra.com/algebra/homework/Triangles/-HOW-TO-bisect-an-angle-using-a-compass-and-a-ruler.lesson>HOW TO bisect an angle using a compass and a ruler</A>\r<BR>\n" );
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document.write( "&nbsp;&nbsp;&nbsp;&nbsp;- <A  rel=nofollow HREF=https://www.algebra.com/algebra/homework/Triangles/How-to-draw-a-congruent-triangle-using-a-compass-and-a-ruler.lesson>HOW TO construct a triangle using a compass and a ruler</A> \r<BR>\n" );
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document.write( "in this site.\r<BR>\n" );
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document.write( "Also, &nbsp;you have this free of charge online textbook on Geometry\r<BR>\n" );
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document.write( "&nbsp;&nbsp;&nbsp;&nbsp;<A  rel=nofollow HREF=https://www.algebra.com/algebra/homework/Triangles/GEOMETRY-your-online-textbook.lesson>GEOMETRY - YOUR ONLINE TEXTBOOK</A> \r<BR>\n" );
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document.write( "in this site.\r<BR>\n" );
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document.write( "The referred lessons are the part of this online textbook under the topic &nbsp;\"<U>Geometric constructions using a compass and a ruler. Basic operations</U>\".\r<BR>\n" );
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document.write( "Save the link to this online textbook together with its description\r<BR>\n" );
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document.write( "Free of charge online textbook in GEOMETRY<BR>\n" );
document.write( "https://www.algebra.com/algebra/homework/Triangles/GEOMETRY-your-online-textbook.lesson\r<BR>\n" );
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document.write( "to your archive and use it when it is needed.\r<BR>\n" );
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document.write( "Notice that the construction algorithm, given in the post by &nbsp;@josmicely, &nbsp;gives you the segment of the length  &nbsp;<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=13%2Fsqrt%282%29 ALIGN=MIDDLE  ALT=\"13%2Fsqrt%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, <BR>\n" );
document.write( "which is &nbsp;<U>totally different</U> &nbsp;from what the problem does require.\r<BR>\n" );
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