document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1129597>Question 1129597</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A local clothing boutique is selling a suit for $99. Because of changing styles, the first markdown was 8% and the second markdown was 25%. The suit still didn't sell, so a final markdown of 10% was taken.\r<BR>\n" );
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document.write( "What's the current sale price?\r<BR>\n" );
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document.write( "A. $86.31<BR>\n" );
document.write( "B. $61.48<BR>\n" );
document.write( "C. $61.84<BR>\n" );
document.write( "D. $68.31\r<BR>\n" );
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document.write( "Need steps please </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #746183 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=746183\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Finding the final sales price by finding the amount of each discount and subtracting three times is VERY inefficient for a problem like this.<br><BR>\n" );
document.write( "When the price is marked down 8%, the original price gets multiplied by 92%, or 0.92.  Similarly, markdowns of 25% and then 10% multiply the price by 0.75 and 0.90.<br><BR>\n" );
document.write( "So after all three markdowns the final price is<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=99%280.92%29%280.75%29%280.90%29+=+61.479 ALIGN=MIDDLE  ALT=\"99%280.92%29%280.75%29%280.90%29+=+61.479\"   DISABLED_style= \"max-width:90%; height:auto;\" > or $61.48, answer B. </SPAN>\n" );
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