document.write( "Question 1129597: A local clothing boutique is selling a suit for $99. Because of changing styles, the first markdown was 8% and the second markdown was 25%. The suit still didn't sell, so a final markdown of 10% was taken.\r
\n" ); document.write( "\n" ); document.write( "What's the current sale price?\r
\n" ); document.write( "\n" ); document.write( "A. $86.31
\n" ); document.write( "B. $61.48
\n" ); document.write( "C. $61.84
\n" ); document.write( "D. $68.31\r
\n" ); document.write( "\n" ); document.write( "Need steps please
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Algebra.Com's Answer #746175 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "if selling a suit for $\"99\" and markdown was \"8\"% =\"0.08\"\r
\n" ); document.write( "\n" ); document.write( "new price was $\"99-0.08%2A99=99-7.92=91.08\"\r
\n" ); document.write( "\n" ); document.write( "and, if the second markdown was \"25\"%=\"0.25\" \r
\n" ); document.write( "\n" ); document.write( "ew price was $\"91.08-0.25%2A91.08=91.08-22.77=68.31\"\r
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\n" ); document.write( "\n" ); document.write( "if a final markdown of \"10\"%=\"0.10\" was taken, \r
\n" ); document.write( "\n" ); document.write( "$\"68.31-0.10%2A68.31=68.31-6.831=61.479\" round it to two decimal places:\r
\n" ); document.write( "\n" ); document.write( "and answer is:\r
\n" ); document.write( "\n" ); document.write( "B. $\"61.48\"\r
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