document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1129586>Question 1129586</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello! Thank you in advance for taking the time to help me!\r<BR>\n" );
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document.write( "The question is: Two planes take off from the same airport at the same time using different runways. One plane travels on a bearing  S15 degreesW at 350 miles per hour. The other plane travels on a bearing N75 degrees E at 250 miles per hour. How far are the planes from each other 3 hours after&#8203; takeoff?\r<BR>\n" );
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document.write( "Answer: The distance is approximately _____ miles (round to the nearest mile as needed)\r<BR>\n" );
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document.write( "I've been stuck on this problem for nearly over an hour and  a half now with countless pieces of paper with my work, however, every time i solve this, I get a different answer and not the right one. I am starting to get very frustrated with this so figured I could ask for some help on how to walk through this problem. Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #746164 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=746164\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two planes take off from the same airport at the same time using different runways. One plane travels on a bearing S15 degrees W at 350 miles per hour. The other plane travels on a bearing N75 degrees E at 250 miles per hour. How far are the planes from each other 3 hours after&#8203; takeoff?<BR>\n" );
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document.write( "S15 degrees W is an azimuth of 270-15 = 255 degrees<BR>\n" );
document.write( "x coordinate after 3 hrs at 350 mph:: 3*350cos(255 deg) = -271.77<BR>\n" );
document.write( "y coordinate after 3 hrs at 350 mph:: 3*350sin(255 deg) = -1014.22<BR>\n" );
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document.write( "N75 degrees E is an azimuth of 90-75 = 15 degrees<BR>\n" );
document.write( "x coordinate after 3hrs at 350 mph:: 3*350cos(15 deg) = 1014.22<BR>\n" );
document.write( "y coordinate aftere 3 hrs at 350 mph:: 3*350sin(15 deg) = 271.80<BR>\n" );
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document.write( "distance = sqrt[(1014.22+271.77)^2 + (1014.22+271.8)^2]<BR>\n" );
document.write( "distance = sqrt[1651790.448+1653847.44] = 1818.14 miles<BR>\n" );
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document.write( "Answer: The distance is approximately 1818 miles (round to the nearest mile as needed)  </SPAN>\n" );
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