document.write( "Question 1129543: A certain distribution of money is distribution to three boys in the ratio of 4:10:18 the difference between largest share and smallest share is 84000. Find the money to be distribution. \n" ); document.write( "
Algebra.Com's Answer #746154 by ankor@dixie-net.com(22740)\"\" \"About 
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A certain distribution of money is distribution to three boys in the ratio of 4:10:18
\n" ); document.write( "let let x = the multiplier
\n" ); document.write( "then to total amt given to the three boys
\n" ); document.write( "4x + 10x + 18x = 32x
\n" ); document.write( ":
\n" ); document.write( "the difference between largest share and smallest share is 84000.
\n" ); document.write( "18x - 4x = 84000
\n" ); document.write( "14x = 84000
\n" ); document.write( "x = 84000/14
\n" ); document.write( "x = 6000 is the multiplier
\n" ); document.write( ":
\n" ); document.write( " Find the money to be distributed.
\n" ); document.write( "32x = total amt
\n" ); document.write( "32 * 6000 = $192,000
\n" ); document.write( ":
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\n" ); document.write( "Check this, find the actual amt each boy got:
\n" ); document.write( "6000(4) = 24000
\n" ); document.write( "6000(10) = 60000
\n" ); document.write( "6000(18) = 108000
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\n" ); document.write( "total amt: 192000
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