document.write( "Question 102591: Write the equation that represents a line passing through (0,5) and is perpendicular to 4x+6y=12 \n" ); document.write( "
Algebra.Com's Answer #74615 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "First convert the standard equation \"4x%2B6y=12\" into slope intercept form\r
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Solved by pluggable solver: Converting Linear Equations in Standard form to Slope-Intercept Form (and vice versa)
Convert from standard form (Ax+By = C) to slope-intercept form (y = mx+b)


\"4x%2B6y=12\" Start with the given equation


\"4x%2B6y-4x=12-4x\" Subtract 4x from both sides


\"6y=-4x%2B12\" Simplify


\"%286y%29%2F%286%29=%28-4x%2B12%29%2F%286%29\" Divide both sides by 6 to isolate y


\"y+=+%28-4x%29%2F%286%29%2B%2812%29%2F%286%29\" Break up the fraction on the right hand side


\"y+=+%28-2%2F3%29x%2B2\" Reduce and simplify


The original equation \"4x%2B6y=12\" (standard form) is equivalent to \"y+=+%28-2%2F3%29x%2B2\" (slope-intercept form)


The equation \"y+=+%28-2%2F3%29x%2B2\" is in the form \"y=mx%2Bb\" where \"m=-2%2F3\" is the slope and \"b=2\" is the y intercept.



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\n" ); document.write( "\n" ); document.write( "Now let's find the equation of the line that is perpendicular to \"y=%28-2%2F3%29x%2B2\" which goes through (0,5)\r
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Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

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\n" ); document.write( " Remember, any two perpendicular lines are negative reciprocals of each other. So if you're given the slope of \"-2%2F3\", you can find the perpendicular slope by this formula:
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\n" ); document.write( " \"m%5Bp%5D=-1%2Fm\" where \"m%5Bp%5D\" is the perpendicular slope
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\n" ); document.write( " \"m%5Bp%5D=-1%2F%28-2%2F3%29\" So plug in the given slope to find the perpendicular slope
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\n" ); document.write( " \"m%5Bp%5D=%28-1%2F1%29%283%2F-2%29\" When you divide fractions, you multiply the first fraction (which is really \"1%2F1\") by the reciprocal of the second
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\n" ); document.write( " \"m%5Bp%5D=3%2F2\" Multiply the fractions.
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\n" ); document.write( " So the perpendicular slope is \"3%2F2\"
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\n" ); document.write( " So now we know the slope of the unknown line is \"3%2F2\" (its the negative reciprocal of \"-2%2F3\" from the line \"y=%28-2%2F3%29%2Ax%2B2\").\n" ); document.write( "Also since the unknown line goes through (0,5), we can find the equation by plugging in this info into the point-slope formula
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\n" ); document.write( " Point-Slope Formula:
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\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
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\n" ); document.write( " \"y-5=%283%2F2%29%2A%28x-0%29\" Plug in \"m=3%2F2\", \"x%5B1%5D=0\", and \"y%5B1%5D=5\"
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\n" ); document.write( " \"y-5=%283%2F2%29%2Ax-%283%2F2%29%280%29\" Distribute \"3%2F2\"
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\n" ); document.write( " \"y-5=%283%2F2%29%2Ax-0%2F2\" Multiply
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\n" ); document.write( " \"y=%283%2F2%29%2Ax-0%2F2%2B5\"Add \"5\" to both sides to isolate y
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\n" ); document.write( " \"y=%283%2F2%29%2Ax-0%2F2%2B10%2F2\" Make into equivalent fractions with equal denominators
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\n" ); document.write( " \"y=%283%2F2%29%2Ax%2B10%2F2\" Combine the fractions
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\n" ); document.write( " \"y=%283%2F2%29%2Ax%2B5\" Reduce any fractions
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\n" ); document.write( " So the equation of the line that is perpendicular to \"y=%28-2%2F3%29%2Ax%2B2\" and goes through (\"0\",\"5\") is \"y=%283%2F2%29%2Ax%2B5\"
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\n" ); document.write( " So here are the graphs of the equations \"y=%28-2%2F3%29%2Ax%2B2\" and \"y=%283%2F2%29%2Ax%2B5\"
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\n" ); document.write( " graph of the given equation \"y=%28-2%2F3%29%2Ax%2B2\" (red) and graph of the line \"y=%283%2F2%29%2Ax%2B5\"(green) that is perpendicular to the given graph and goes through (\"0\",\"5\")
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