document.write( "Question 1129576: The function N(x)= 40,000/1+20e^-1.5 describes the number of people, N(t), who become ill with a virus t weeks after its initial outbreak in a town with 40 comma 000 inhabitants. The horizontal asymptote in the graph indicates that there is a limit to the epidemic's growth. Complete parts (a) through (c) below. \r
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document.write( "a. How many people became ill with the virus when the epidemic began? (When the epidemic began, t=0.)\r
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document.write( "When the epidemic began, approximately 1905 people were ill with the virus.
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document.write( "(Round to the nearest person as needed.). I got the answer!\r
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document.write( "b. How many people were ill by the end of the second week?\r
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document.write( "By the end of the second week, approximately____________people were ill with the virus.
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document.write( "(Round to the nearest person as needed.) \r
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document.write( "ASAP Please and thank you! \n" );
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Algebra.Com's Answer #746139 by Boreal(15235) You can put this solution on YOUR website! N(x)= 40,000/1+20e^-1.5t, editing in the t \n" ); document.write( "When t=0, e^0=1 \n" ); document.write( "40000/21=1905 \r \n" ); document.write( "\n" ); document.write( "after two weeks I am assuming t=14 and this is in days not hours or some other unit.\r \n" ); document.write( "\n" ); document.write( "=40000/(1+20e^(-21)), the 21 coming from 14*(1.5), and that number is essentially 0, so the denominator is 1. \n" ); document.write( "That makes N(x)=40000 people, if the above assumptions are correct. It is important to know where the x is. \n" ); document.write( " |