document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1129485>Question 1129485</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3 less than 5 times the width. the perimeter is 10 times the width find the demensions.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #746097 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=746097\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Let the width be w.  Then the problem tells us the length is 3 less than 5 times the width:<br><BR>\n" );
document.write( "l = 5w-3<br><BR>\n" );
document.write( "We are also told that the perimeter (2l+2w) is 10 times the width:<br><BR>\n" );
document.write( "2l+2w = 10w<BR>\n" );
document.write( "2l = 8w<BR>\n" );
document.write( "l = 4w<br><BR>\n" );
document.write( "We have two different expressions for the length in terms of the width; those two expressions must be equal:<br><BR>\n" );
document.write( "5w-3 = 4w<BR>\n" );
document.write( "w = 3<br><BR>\n" );
document.write( "l = 4w = 12<br><BR>\n" );
document.write( "The rectangle is 12x3. </SPAN>\n" );
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