document.write( "Question 1129453: Solve. \r
\n" ); document.write( "\n" ); document.write( "2/3x+7=9
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Algebra.Com's Answer #746037 by JoelSchwartz(130)\"\" \"About 
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(2/3)x+7=9
\n" ); document.write( "(2/3)x+7-7=9-7
\n" ); document.write( "(2/3)x=2
\n" ); document.write( "3(2/3)x=2*3
\n" ); document.write( "2x=6
\n" ); document.write( "2x/2=6/2
\n" ); document.write( "x=3
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