document.write( "Question 1129450: In a random sample of 24 people, the mean commute time to work was 30.8 minutes and the standard deviation was 7.1 minutes. Assume the population is normally distributed and use a t-distribution to construct a 95% confidence interval for the population mean mu. What is the margin of error of mu? Interpret the results.
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document.write( "The confidence interval for the population mean mu is left parenthesis comma right parenthesis .
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document.write( "(Round to one decimal place as needed.)
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document.write( "The margin of error of mean is:
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document.write( "(Round to one decimal place as needed.)
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document.write( "Interpret the results.
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document.write( "A.
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document.write( "It can be said that 95% of people have a commute time between the bounds of the confidence interval.
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document.write( "B.
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document.write( "With 95% confidence, it can be said that the commute time is between the bounds of the confidence interval.
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document.write( "C.
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document.write( "With 95% confidence, it can be said that the population mean commute time is between the bounds of the confidence interval.
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document.write( "D.
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document.write( "If a large sample of people are taken approximately 95% of them will have commute times between the bounds of the confidence interval. \n" );
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Algebra.Com's Answer #746032 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! t df=23,0.975=2.069 \n" ); document.write( "s=7.1 \n" ); document.write( "ts/sqrt(n) is half interval or 2.069*7.1/sqrt(24)=3.0 ANSWER \n" ); document.write( "(27.8, 33.8)units minutes\r \n" ); document.write( "\n" ); document.write( "C \n" ); document.write( "The purpose of a confidence interval is to define where the true mean lies, with a certain degree of confidence. The true mean is usually unknown and unknowable and either lies in or out of the interval. We don't know which, and it is a 100-0 type of issue, which is why we use confidence for where we think the true mean lies, not a probability. \n" ); document.write( " |