document.write( "Question 1129423: Part of the proceeds from a garage sale was $265 worth of $5 and $20 bills. If there were 3 more $5 bills than $20 bills. Find the number of each denomination
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document.write( " There were ? $5 bills and ? $20 bills \n" );
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Algebra.Com's Answer #745993 by ikleyn(52781)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "Put aside that three extra $5 bills.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Then you have an updated collection of equal number of $5 and $20 dollars bills, and this collection is worth 265 - 15 = 250 dollars.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Now you can group $5 and $20 dollar bills in sets containing one $5-dollar bill and one $20-dollar bill.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Each set is worth $25, and the number of sets is\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |