document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1129393>Question 1129393</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use a system of linear equations with two variables and two equations to solve. \r<BR>\n" );
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document.write( "A number is 11 more than another number. Twice the sum of the two numbers is 10. Find the two numbers. (Enter your answers as a comma-separated list.) <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #745951 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=745951\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y = x+11<BR>\n" );
document.write( "2(y+x) = 10 substitute y with equivalent above:<BR>\n" );
document.write( "2(x+11+x) = 10<BR>\n" );
document.write( "2x+22+2x = 10<BR>\n" );
document.write( "4x = -12<BR>\n" );
document.write( "x = -3<BR>\n" );
document.write( "and<BR>\n" );
document.write( "y = x+11 = -3+11 = 8<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "Twice the sum of the two numbers is 10<BR>\n" );
document.write( "2(8+-3)= 16+-6 = 10 Correct </SPAN>\n" );
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