document.write( "Question 1129377: The two sides of the triangle ABC has sides AB=22cm and AC=8. If the area of the triangle 34.98 cm², what is it's perimeter? \n" ); document.write( "
Algebra.Com's Answer #745937 by MathLover1(20850)\"\" \"About 
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the triangle \"ABC\" has sides:
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\n" ); document.write( "\"AB=22cm\"
\n" ); document.write( "\"AC=8cm\"
\n" ); document.write( "and \"A=34.98cm%5E2\"\r
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\n" ); document.write( "\n" ); document.write( " If the area of the triangle \"A=34.98cm%5E2\" and \"AB=22cm\", we have\r
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\n" ); document.write( "\n" ); document.write( "\"34.98cm%5Ecross%282%29=%2822cross%28cm%29%2Ah%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"34.98cm=11%2Ah\"\r
\n" ); document.write( "\n" ); document.write( "\"34.98cm%2F11=h\"\r
\n" ); document.write( "\n" ); document.write( "\"h=3.18cm\"\r
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\n" ); document.write( "\n" ); document.write( "find \"BC\"-> note that \"h\" divides triangle in two right triangles and side \"AB=22cm\" in two parts \"x\" and \"y\"\r
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\n" ); document.write( "\n" ); document.write( "since we know \"AC=8\", \"h=3.18cm\",
\n" ); document.write( "use Pythagorean theorem to find \"x\"
\n" ); document.write( " \"x=sqrt%288%5E2-3.18%5E2%29\"
\n" ); document.write( " \"x=7.34\"\r
\n" ); document.write( "\n" ); document.write( "then, \"y=22-7.34\"->\"y=14.66\"\r
\n" ); document.write( "\n" ); document.write( "now use Pythagorean theorem to find \"BC\"\r
\n" ); document.write( "\n" ); document.write( "\"y=14.66\", and \"h=3.18\"\r
\n" ); document.write( "\n" ); document.write( " \"BC=sqrt%2814.66%5E2%2B3.18%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"BC=15.0009%29\"\r
\n" ); document.write( "\n" ); document.write( "\"BC=15cm\"\r
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\n" ); document.write( "\n" ); document.write( "what is it's perimeter? \r
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\n" ); document.write( "\n" ); document.write( "\"P=AB%2BAC%2BBC\"\r
\n" ); document.write( "\n" ); document.write( "\"P=22cm%2B8cm%2B15cm\"\r
\n" ); document.write( "\n" ); document.write( "\"P=45cm\"\r
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\n" ); document.write( "\n" ); document.write( "or, this way:\r
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\n" ); document.write( "\n" ); document.write( "Use the formula \r
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\n" ); document.write( "\n" ); document.write( " \"Area+=%281%2F2%29%2Aa%2Ab%2Asin%28alpha%29\" for the area of a triangle, \r
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\n" ); document.write( "\n" ); document.write( "where \"a\" and \"b\" are two sides lengths and \"alpha\" is the angle between them.\r
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\n" ); document.write( "\n" ); document.write( "Using given data, find \"sin%28alpha%29\".\r
\n" ); document.write( "\n" ); document.write( " \"34.98=%281%2F2%29%2A22%2A8%2Asin%28alpha%29\"\r
\n" ); document.write( "\n" ); document.write( "\"34.98=88%2Asin%28alpha%29\"\r
\n" ); document.write( "\n" ); document.write( "\"sin%28alpha%29=34.98%2F88\"
\n" ); document.write( "\"sin%28alpha%29=0.3975\"
\n" ); document.write( "\"alpha=sin%5E-1%280.3975%29\"
\n" ); document.write( "\"alpha=sin%5E-1%280.3975%29\"
\n" ); document.write( "\"alpha=23.42\"°\r
\n" ); document.write( "\n" ); document.write( "Having \"%28alpha%29\", find \"cos%28alpha%29\".
\n" ); document.write( "\"cos%2823.42%29=0.917616\"\r
\n" ); document.write( "\n" ); document.write( "Then find the length of the third side using the cosine law.
\n" ); document.write( " \"c%5E2+=+a%5E2+%2B+b%5E2+%26%238722%3B+2ab+cos%28alpha%29\"
\n" ); document.write( " \"c%5E2+=+22%5E2+%2B+8%5E2+%26%238722%3B+2%2A22%2A8%2A0.917616\"
\n" ); document.write( " \"c%5E2+=+224.999168\"
\n" ); document.write( " \"c+=+sqrt%28225%29\"
\n" ); document.write( " \"c+=+15\"\r
\n" ); document.write( "\n" ); document.write( "Then find the perimeter,\r
\n" ); document.write( "\n" ); document.write( "\"P=a%2Bb%2Bc\"\r
\n" ); document.write( "\n" ); document.write( "\"P=22cm%2B8cm%2B15cm\"\r
\n" ); document.write( "\n" ); document.write( "\"P=45cm\"\r
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