document.write( "Question 1129377: The two sides of the triangle ABC has sides AB=22cm and AC=8. If the area of the triangle 34.98 cm², what is it's perimeter? \n" ); document.write( "
Algebra.Com's Answer #745936 by ikleyn(52803)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\"highlight%28cross%28The%29%29\" \"highlight%28cross%28two%29%29\" \"highlight%28cross%28sides%29%29\" \"highlight%28cross%28of%29%29\" \"highlight%28cross%28the%29%29\" Triangle ABC has sides AB=22cm and AC=8. If the area of the triangle 34.98 cm², what is it's perimeter?
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document.write( "Use the formula \r\n" );
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document.write( "   Area = \"%281%2F2%29%2Aa%2Ab%2Asin%28alpha%29\" for the area of a triangle, \r\n" );
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document.write( "where \"a\" and \"b\" are two sides lengths and  \"alpha\"  is the angle between them.\r\n" );
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document.write( "Using given data, find \"sin%28alpha%29\".\r\n" );
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document.write( "Having  \"sin%28alpha%29\",  find \"cos%28alpha%29\" = +/-\"sqrt%281-sin%5E2%28alpha%29%29\".\r\n" );
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document.write( "    ===---> > > Notice that there is NO NEED to find \"alpha\" : all you need is \"sin%28alpha%29\". < < <---===\r\n" );
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document.write( "Then find the length of the third side using  the cosine law.\r\n" );
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document.write( "Then find the perimeter,\r\n" );
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\n" ); document.write( "\n" ); document.write( "By the way,  since  \"cos%28alpha%29\"  may have  (and factually has (!))  TWO values at given  \"sin%28alpha%29\",  you will have
\n" ); document.write( "TWO possible values for the third side,  and,  correspondingly,  TWO values for the possible perimeter.\r
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\n" ); document.write( "\n" ); document.write( "Regrading the solution by the tutor  @Mathlover1,  keep in mind that she loss one possible answer and makes
\n" ); document.write( "a lot of unnecessary calculations on her way  (like finding  \"alpha\" ).\r
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