document.write( "Question 1129355: how many pounds of a 16% aluminum alloy must be mixed with 300lb of a 37% aluminum alloy to make a 22% aluminum alloy? \n" ); document.write( "
Algebra.Com's Answer #745923 by ankor@dixie-net.com(22740)\"\" \"About 
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how many pounds of a 16% aluminum alloy must be mixed with 300lb of a 37% aluminum alloy to make a 22% aluminum alloy?
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\n" ); document.write( "let x = 16% alloy
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\n" ); document.write( "The mixture equation
\n" ); document.write( ".16x + .37(300) = .22(x+300)
\n" ); document.write( ".16x + 111 = .22x + 66
\n" ); document.write( ".16x - .22x = 66 - 111
\n" ); document.write( "-.06x = -45
\n" ); document.write( "x = -45/-.06
\n" ); document.write( "x = +750 lb of 16% alloy required
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\n" ); document.write( "Check this yourself
\n" ); document.write( ".16(750) + .37(300) = .22(750+300) \n" ); document.write( "
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