document.write( "Question 1129332: a. Show that the point Q(6,2) lies on the circle x^2+y^2-4x+2y-20
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Algebra.Com's Answer #745907 by MathLover1(20849)\"\" \"About 
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a. Show that the point Q(\"6\",\"2\") lies on the circle \r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2By%5E2-4x%2B2y-20\"
\n" ); document.write( "\"6%5E2%2B2%5E2-4%2A6%2B2%2A2-20\"
\n" ); document.write( "\"36%2B4-24%2B4-20\"
\n" ); document.write( "\"44-44\"
\n" ); document.write( "\"0\"=>the point Q(\"6\",\"2\") lies on the circle\r
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\n" ); document.write( "\n" ); document.write( "b. Find the equation of tangent to the circle at point Q \r
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\n" ); document.write( "\n" ); document.write( "As a tangent is a straight line it is described by an equation in the form
\n" ); document.write( "\"+y+-+y%5B1%5D+=+m%28x+-x%5B1%5D%29\". \r
\n" ); document.write( "\n" ); document.write( "You need both a \"point\" and the \"slope\" to find its equation.\r
\n" ); document.write( "\n" ); document.write( "You are usually given the point - it's where the tangent meets the circle.\r
\n" ); document.write( "\n" ); document.write( "To find the \"slope\" use the fact that the tangent is \"perpendicular\" to the \"radius\" from the point it meets the circle.\r
\n" ); document.write( "\n" ); document.write( "Work out the slope of the \"radius\" (r) at the point the tangent meets the circle. Then use the equation \"+m_tg+=+-+1%2Fm_r\" to find the gradient of the tangent.\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2-4x%29%2B%28y%5E2%2B2y%29=20\"...if you complete squares, you will see that the center of the circle is (\"2\",\"-1\")\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2-4x%2Bb%5E2%29-b%5E2%2B%28y%5E2%2B2y%2Bb%5E2%29-b%5E2=20\"
\n" ); document.write( "\"%28x%5E2-4x%2B2%5E2%29-2%5E2%2B%28y%5E2%2B2y%2B1%5E2%29-b%5E2=20\"
\n" ); document.write( "\"%28x-2%29%5E2%29-4%2B%28y%2B1%29%5E2%29-1=20\"
\n" ); document.write( "\"%28x-2%29%5E2%29%2B%28y%2B1%29%5E2%29=25\"\r
\n" ); document.write( "\n" ); document.write( "Q(\"6\",\"2\") and (\"2\",\"-1\")=>\r
\n" ); document.write( "\n" ); document.write( " the slope of the radius \r
\n" ); document.write( "\n" ); document.write( "\"m_r=%28-1-2%29%2F%282-6%29=-3%2F-4=3%2F4\"\r
\n" ); document.write( "\n" ); document.write( "the slope of the tangent is \"m_tg=-1%2F%283%2F4%29=-4%2F3\"\r
\n" ); document.write( "\n" ); document.write( "and equation af the tangent is:\r
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\n" ); document.write( "\n" ); document.write( "Q(\"6\",\"2\") ,\"m_tg=-4%2F3\"\r
\n" ); document.write( "\n" ); document.write( " \"y+-+2+=+-%284%2F3%29%28x+-6%29\"
\n" ); document.write( "\"y++=+-%284%2F3%29x+-6%28-4%2F3%29%2B2\"
\n" ); document.write( "\"y++=+-%284%2F3%29x+%2B8%2B2\"
\n" ); document.write( "\"y++=+-%284%2F3%29x+%2B10\"\r
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