document.write( "Question 102565: A solar collector is 2.5 m long by 2.0 m wide. It is held in place by a frame of uniform width around its outside edge. If the exposed collector is 4 m2, what is the width of the frame to the nearest tenth of a centimeter? \n" ); document.write( "
Algebra.Com's Answer #74588 by josmiceli(19441)\"\" \"About 
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\"2%2A2.5+=+5\"
\n" ); document.write( "If the exposed area is \"4\", then the area of the
\n" ); document.write( "frame is \"1\"
\n" ); document.write( "Call the width of the frame \"x\"
\n" ); document.write( "Then \"2.5x+%2B+2.5x+%2B+x%282+-+2x%29+%2B+x%282+-+2x%29+=+1\"
\n" ); document.write( "\"5x+%2B+2x%282+-+2x%29+=+1\"
\n" ); document.write( "\"5x+%2B+4x+-+4x%5E2+=+1\"
\n" ); document.write( "\"4x%5E2+-+9x+%2B+1+=+0\"
\n" ); document.write( "This is in the form
\n" ); document.write( "\"ax%5E2+%2B+bx+%2B+c+=+0\"
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "\"x+=+%28-%28-9%29+%2B-+sqrt%28+%28-9%29%5E2-4%2A4%2A1+%29%29%2F%282%2A4%29+\"
\n" ); document.write( "\"x+=+%289+%2B-+sqrt%2881+-+16%29%29+%2F+8\"
\n" ); document.write( "\"x+=+%289+%2B-+sqrt%2865%29%29+%2F+8\"
\n" ); document.write( "\"x+=+%289+%2B-+8.062%29+%2F+8\"
\n" ); document.write( "\"x+=+%289+-+8.062%29+%2F+8\" gives the only reasonable answer
\n" ); document.write( "\"x+=+.117\" m, or
\n" ); document.write( "\"x+=+11.7\" cm answer
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