document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1129295>Question 1129295</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could someone please help explain how to solve for the years: <BR>\n" );
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document.write( "The population of a small town is modeled by the equation <BR>\n" );
document.write( "P = 1650e^0.5t where t is measured in years. In approximately how many years will the town's population reach 20,000? (Round your answer to two decimal places.) \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #745850 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=745850\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The population of a small town is modeled by the equation <BR>\n" );
document.write( "P = 1650e^0.5t where t is measured in years. In approximately how many years will the town's population reach 20,000? (Round your answer to two decimal places.) <BR>\n" );
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document.write( "Solve for \"t\"::<BR>\n" );
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document.write( "20,000 = 1650*e^(0.5t)<BR>\n" );
document.write( "e^(0.5t) = 12.12<BR>\n" );
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document.write( "Since the variable is in the exponent, take the ln of both sides to get:<BR>\n" );
document.write( "0.5t = ln(12.12) = 2.495<BR>\n" );
document.write( "t =  4.99 years<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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